On Fri, Mar 08, 2002 at 03:16:10PM +0100, Marcelo E. Magallon wrote:
>
> A question of my own: why doesn't
>
> s/\B.\B/$&$&/g
>
> work as I expect, namely abcd -> abbccd. I really can't figure it out
> by reading the docs.
Because after matching the b and the non-boundaries around it, the
non-boundary between b and c already matched. So the next match for
non-boundary will match between c and d, and since there is no \B
after d, you'll get abbcd.
You can try to rewrite the regexp as
s/_(.)_/$+$+/g;
and match
a_b_c_d
Here, it should be obvious that after matching _b_, your next chance
with _ is between c and d, not between b and c.
Yours,
--
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Honza Pazdziora | [EMAIL PROTECTED] | http://www.fi.muni.cz/~adelton/
... all of these signs saying sorry but we're closed ...
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