Marcelo E. Magallon <[EMAIL PROTECTED]> wrote: > A question of my own: why doesn't > > s/\B.\B/$&$&/g > > work as I expect, namely abcd -> abbccd. I really can't figure it > out by reading the docs.
I wondered that too. I figured it was because \B wouldn't match twice at the same place, but then I saw that s/\B./$&$&/g didn't work as expected either. -- Keith C. Ivey <[EMAIL PROTECTED]> Washington, DC
