file  *api/authenticate.py*

class AuthenticationController( BaseAPIController, CreatesApiKeysMixin ):

    @web.expose_api_anonymous
    def get_api_key( self, trans, **kwd ):
        """
        def get_api_key( self, trans, **kwd )
        * *GET /api/authenticate/baseauth*
          returns an API key for authenticated user based on BaseAuth
headers

        :returns: api_key in json format
        :rtype:   dict

        :raises: ObjectNotFound, HTTPBadRequest
        """


On Mon, Jul 21, 2014 at 10:06 AM, Eric Rasche <rasche.e...@yandex.ru> wrote:

> John,
>
> I'm looking to use blend4j, and I was wondering if there was a way to
> obtain the user's API key from a username/password pair?
>
> Cheers,
> Eric
>
> --
> Eric Rasche
> Programmer II
> Center for Phage Technology
> Texas A&M Univesity
> College Station, TX 77843
> Ph: 4046922048 <http://tel:4046922048>
>
>
>
> ___________________________________________________________
> Please keep all replies on the list by using "reply all"
> in your mail client.  To manage your subscriptions to this
> and other Galaxy lists, please use the interface at:
>   http://lists.bx.psu.edu/
>
> To search Galaxy mailing lists use the unified search at:
>   http://galaxyproject.org/search/mailinglists/
>
___________________________________________________________
Please keep all replies on the list by using "reply all"
in your mail client.  To manage your subscriptions to this
and other Galaxy lists, please use the interface at:
  http://lists.bx.psu.edu/

To search Galaxy mailing lists use the unified search at:
  http://galaxyproject.org/search/mailinglists/

Reply via email to