Sorry for missleading typo.

>> VNx1BI: vsevl e8mf8 + vlm,  loading 1/8 of poly (1,1) storage.
>> VNx2BI: vsevl e8mf8 + vlm,  loading 1/4 of poly (1,1) storage.
>> VNx4BI: vsevl e8mf8 + vlm,  loading 1/2 of poly (1,1) storage.
>> VNx8BI: vsevl e8mf8 + vlm,  loading 1 of poly (1,1) storage.

It should be:
 VNx1BI: vsevl e8mf8 + vlm,  loading 1/8 of poly (1,1) storage.
 VNx2BI: vsevl e8mf4 + vlm,  loading 1/4 of poly (1,1) storage.
 VNx4BI: vsevl e8mf2 + vlm,  loading 1/2 of poly (1,1) storage.
 VNx8BI: vsevl e8m1 + vlm,  loading 1 of poly (1,1) storage.

Plz be aware of this . Thanks. 


juzhe.zh...@rivai.ai
 
From: juzhe.zh...@rivai.ai
Date: 2023-03-01 21:50
To: richard.sandiford; gcc-patches
CC: rguenther; Pan Li; pan2.li; kito.cheng
Subject: Re: Re: [PATCH] RISC-V: Bugfix for rvv bool mode precision adjustment
Let's me first introduce RVV load/store basics  and stack allocation.
For scalable vector memory allocation, we allocate memory according to machine 
vector-length.
To get this CPU vector-length value (runtime invariant but compile time 
unknown), we have an instruction call csrr vlenb.
For example, csrr a5,vlenb (store CPU a single register vector-length value 
(describe as bytesize) in a5 register).
A single register size in bytes (GET_MODE_SIZE) is poly value (8,8) bytes. That 
means csrr a5,vlenb, a5 has the value of size poly (8,8) bytes.

Now, our problem is that VNx1BI, VNx2BI, VNx4BI, VNx8BI has the same bytesize 
poly (1,1). So their storage consumes the same size.
Meaning when we want to allocate a memory storge or stack for register 
spillings, we should first csrr a5, vlenb, then slli a5,a5,3 (means a5 = a5/8)
Then, a5 has the bytesize value of poly (1,1). All VNx1BI, VNx2BI, VNx4BI, 
VNx8BI are doing the same process as I described above. They all consume
the same memory storage size since we can't model them accurately according to 
precision or you bitsize.

They consume the same storage (I am agree it's better to model them more 
accurately in case of memory storage comsuming).

Well, even though they are consuming same size memory storage, I can make their 
memory accessing behavior (load/store) accurately by
emiting  the accurate RVV instruction for them according to RVV ISA.

VNx1BI,VNx2BI, VNx4BI, VNx8BI are consuming same memory storage with size  poly 
(1,1)
The instruction for these modes as follows:
VNx1BI: vsevl e8mf8 + vlm,  loading 1/8 of poly (1,1) storage.
VNx2BI: vsevl e8mf8 + vlm,  loading 1/4 of poly (1,1) storage.
VNx4BI: vsevl e8mf8 + vlm,  loading 1/2 of poly (1,1) storage.
VNx8BI: vsevl e8mf8 + vlm,  loading 1 of poly (1,1) storage.

So base on these, It's fine that we don't model VNx1BI,VNx2BI, VNx4BI, VNx8BI 
accurately according to precision or bitsize.
This implementation is fine even though their memory storage is not accurate.

However, the problem is that since they have the same bytesize, GCC will think 
they are the same and do some incorrect statement elimination:

(Note: Load same memory base)
load v0 VNx1BI from base0
load v1 VNx2BI from base0
load v2 VNx4BI from base0
load v3 VNx8BI from base0

store v0 base1
store v1 base2
store v2 base3
store v3 base4

This program sequence, in GCC, it will eliminate the last 3 load instructions.

Then it will become:

load v0 VNx1BI from base0 ===> vsetvl e8mf8 + vlm (only load 1/8 of poly size 
(1,1) memory data)

store v0 base1
store v0 base2
store v0 base3
store v0 base4

This is what we want to fix. I think as long as we can have the way to 
differentiate VNx1BI,VNx2BI, VNx4BI, VNx8BI
and GCC will not do th incorrect elimination for RVV. 

I think it can work fine  even though these 4 modes consume inaccurate memory 
storage size
but accurate data memory access load store behavior.

Thanks.


juzhe.zh...@rivai.ai
 
From: Richard Sandiford
Date: 2023-03-01 21:19
To: Pan Li via Gcc-patches
CC: Richard Biener; Pan Li; juzhe.zhong\@rivai.ai; pan2.li; Kito.cheng
Subject: Re: [PATCH] RISC-V: Bugfix for rvv bool mode precision adjustment
Pan Li via Gcc-patches <gcc-patches@gcc.gnu.org> writes:
> I am not very familiar with the memory pattern, maybe juzhe can provide more 
> information or correct me if anything is misleading.
>
> The different precision try to resolve the below bugs, the second vlm(with 
> different size of load bytes compared to first one)
> is eliminated because vbool8 and vbool16 have the same precision size, aka 
> [8, 8].
>
> vbool8_t v2 = *(vbool8_t*)in;
> vbool16_t v5 = *(vbool16_t*)in;
> *(vbool16_t*)(out + 200) = v5;
> *(vbool8_t*)(out + 100) = v2;
>
> addi    a4,a1,100
> vsetvli a5,zero,e8,m1,ta,ma
> addi    a1,a1,200
> vlm.v   v24,0(a0)
> vsm.v   v24,0(a4)
> // Need one vsetvli and vlm.v for correctness here.
> vsm.v   v24,0(a1)
 
But I think it's important to think about the patch as more than a way
of fixing the bug above.  The aim has to be to describe the modes as they
really are.
 
I don't think there's a way for GET_MODE_SIZE to be "conservatively wrong".
A GET_MODE_SIZE that is too small would cause problems.  So would a
GET_MODE_SIZE that is too big.
 
Like Richard says, I think the question comes down to the amount of padding.
Is it the case that for 4+4X ([4,4]), the memory representation has 4 bits
of padding for even X and 0 bits of padding for odd X?
 
I agree getting rid of GET_MODE_SIZE and representing everything in bits
would avoid the problem at this point, but I think it would just be pushing
the difficulty elsewhere.  E.g. stack layout will be "interesting" if we
can't work in byte sizes.
 
Thanks,
Richard
 

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