On 20 July 2011 00:45, Cheng Renquan wrote: > On Tue, Jul 19, 2011 at 4:18 PM, Jonathan Wakely <jwakely....@gmail.com> > wrote: >> This question is more suitable for the gcc-help list, as it is a >> question about using gcc not about developing it. > > What I insist to discuss here is I think this may be a gcc's bug,
This isn't the right list for that either. Questions about using gcc should go to gcc-help, bug reports should go to bugzilla. > could be fixed in some future day? It's not a bug, it's how unions work. >> What you want is not supported. The member of the union that is >> initialized will either be the int[3], or the short[6], or the >> char[12]. You cannot initialize some bytes of one member and some >> bytes of another like that. > > Do you know why is it not supported? Is there some standard (like > C99?) forbid to > implement it? C99 doesn't even support .c[6] syntax for initializers, it's a GCC extension. > Otherwise we could see it as a gcc bug; I don't think so. >> >> Maybe you should just do this instead: >> >> union mbox mbox = { .c[0] = 1, .c[4] = 2, .c[6] = 's' }; > > Sorry, my above still not a good example, what I mean to initialize is > .w[0] is a real 4 bytes integer, .s[2] is real short, those are not > convenient to write in .c[...]; > > like this example: > > union mbox mbox = { .w[0] = 0x12345678, .s[2] = 0xabcd, .c[6] = 's' }; > > I tried hexdump again, only last one .c[6] was initialized, > > I think to initialize .w[0] / .s[2] / .c[6] have no conflict with each > other, why can't we implement such behavior? Because only one union member can be initialized, and the union members are w, s, and c, not w[0] etc. If you want finer-grained control of sub-objects of the union members then set the elements later via assignment, instead of trying to do it via initialization.