On Tue, Oct 25, 2011 at 11:12:25AM +0200, Frederic Riss wrote: > Could you explain why the overflow is required here with respect to > the standard?
Because most of gcc targets (the only exception is i386 and m68k I think)
define FLT_EVAL_METHOD 0, so say that floating point expressions are
evaluated to the range and precision of corresponding type.
And that is quite desirable behavior for many applications.
Jakub
