Hi,
I am slightly confused about the BIGGEST_ALIGNMENT docs which state:
"Biggest alignment that any data type can require on this machine, in bits.
Note that this is not the biggest alignment that is supported, just the biggest
alignment that, when violated, may cause a fault."
What kind of fault would this be?
We currently have it set to 64, word_size. However, we really have no alignment
restrictions being able to align data types to byte boundaries if necessary.
Therefore, from this piece of code:
unsigned int
get_mode_alignment (enum machine_mode mode)
{
return MIN (BIGGEST_ALIGNMENT, MAX (1, mode_base_align[mode]*BITS_PER_UNIT));
}
I am tempted to set BIGGEST_ALIGNMENT to 8 so I can force GCC to just align the
data at any byte boundary. Would this be a fair use of BIGGEST_ALIGNMENT? If
not, then should BIGGEST_ALIGNMENT be equal to the largest supported mode on
our machine? I am quite confused about what fault it could happen in
BIGGEST_ALIGNMENT is violated, therefore for our machine I guess
BIGGEST_ALIGNMENT can be as high as possible.
Paulo Matos
