Similar to another ongoing thread, I am needing to convert imagery to 8 bit
to display in my own viewer.
This has presented me with a few issues. It seems like no matter what of the
GDALDataTypes I perform a sizeof() operation on, be it GDT_Byte or GDT_Float32,
the size is always 4 bytes.
I am trying to use RasterIO presently to display image. As it turns out, if i
run a gdalinfo on the image, i see that it uses uint16 as the Type, but only
uses 11 bits per pixel actually!
Since the data types all had a sizeof() = 4, I allocated a float, and I have
been reading the data like so
float * floatData = (float *) CPLMalloc(sizeof(float)*nXSize*nYSize);
poBand->RasterIO( GF_Read, 0, 0, nXSize, nYSize, floatData, nXSize,
nYSize,GDT_Float32, 0, 0 );
This seems to be working presently at getting the data, however, I have to use
a scaling function like so:
float two_eight = pow(2.0,8);
float two_eleven = pow(2.0,11);
for (int i = 0 ; i < imheight ; i++)
{
for (int j = 0 ; j < imwidth ; j++)
{
floatData[i*imwidth+j] = (two_eight*
floatData[i*imwidth+j])/two_eleven;
}
}
Which is obviously not ideal, especially when you consider I still have to cast
this to unsigned char to be displayed.
My question is - is there a better way to have this conversion done for me? I
tried to allocated my data as unsigned char, and read in a GDT_Byte, but the
image looked bad. If I continue with this way, is there a way to dynamically
figure out the actual bits per pixel from the band? It is not clear to me from
the API how this was performed, as it seems like it is buried in the nitf image
format code in the example application.
Thanks
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