You can also do it without the or in the predicate by comparing to a sequence
of locales you want to match on.
-Will
let $x :=
<languages>
<language iso3="ita"/>
<language iso3="fra"/>
<language iso3="slv"/>
<language iso3="deu"/>
<language iso3="eng"/>
</languages>
return
($x/language[@iso3 = ("fra", "eng")])[1]
From: [email protected]
[mailto:[email protected]] On Behalf Of sini narayanan
Sent: Friday, May 10, 2013 12:17 AM
To: MarkLogic Developer Discussion
Subject: Re: [MarkLogic Dev General] xquery - get position of a node
Thanks. It was helpful.
Regards,
Sini
On Fri, May 10, 2013 at 11:33 AM, Fahad Khan
<[email protected]<mailto:[email protected]>> wrote:
Hi,
To get the first available language "fra" or "eng", I would use:
let $x :=
<languages>
<language iso3="ita"/>
<language iso3="fra"/>
<language iso3="slv"/>
<language iso3="deu"/>
<language iso3="eng"/>
</languages>
return ($x/language[@iso3="fra" or @iso3="eng"])[1]
If you really want the position, something like:
($x/language[@iso3="fra" or
@iso3="eng"])[1]/fn:count(preceding-sibling::language) + 1
Hope that helps.
Cheers,
Fahad.
On 05/10/2013 06:52 AM, sini narayanan wrote:
Hi All,
I have an xml document with different language nodes.
for example:
<languages>
<language iso3="ita"/>
<language iso3="fra"/>
<language iso3="slv"/>
<language iso3="deu"/>
<language iso3="eng"/>
</languages>
I need to fid out, the first available language "fra" or "eng". (If "fra" node
comes first or "eng" comes first)
Which is the best way to do this ?
Is ther a way to get the position of a node in xquery?
Thanks,
Sini
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