Not sure where "billed elsewhere" is ... but the W3C spec is fairly clear (if complex)
http://www.w3.org/TR/xmlschema-2/#dateTime The ·lexical space·<http://www.w3.org/TR/xmlschema-2/#dt-lexical-space> of dateTime consists of finite-length sequences of characters of the form: '-'? yyyy '-' mm '-' dd 'T' hh ':' mm ':' ss ('.' s+)? (zzzzzz)?, where That includes the possibility of fractional seconds and something other then Z for the timezone. ----- * '.' s+ (if present) represents the fractional seconds; * zzzzzz (if present) represents the timezone (as described below). For example, 2002-10-10T12:00:00-05:00 (noon on 10 October 2002, Central Daylight Savings Time as well as Eastern Standard Time in the U.S.) is 2002-10-10T17:00:00Z, five hours later than 2002-10-10T12:00:00Z. ----------------------------------------------------------------------------- David Lee Lead Engineer MarkLogic Corporation [email protected] Phone: +1 812-482-5224 Cell: +1 812-630-7622 www.marklogic.com<http://www.marklogic.com/> From: [email protected] [mailto:[email protected]] On Behalf Of [email protected] Sent: Saturday, May 11, 2013 6:17 PM To: MarkLogic Developer Discussion Subject: Re: [MarkLogic Dev General] return current dateTime in UTC format Ron (and David), Thanks. Yes, it "felt a bit wrong" to me too to have to slice and dice the dateTime as a string. I thought since this: 2013-05-11T17:01:18Z is billed elsewhere as "the standard W3C date and time format" that there was probably a built-in function for it. Morgan ________________________________ From: "Ron Hitchens" <[email protected]> To: "MarkLogic Developer Discussion" <[email protected]> Sent: Saturday, May 11, 2013 5:28:29 PM Subject: Re: [MarkLogic Dev General] return current dateTime in UTC format Try something like this (using XQuery 3.0 concatenation syntax): declare variable $orig-time := xs:dateTime ("2013-05-11T10:38:45.333548-04:00"); declare variable $utc-time := fn:adjust-dateTime-to-timezone ($orig-time, xs:dayTimeDuration('PT0H')); declare variable $adjusted-time := xs:dateTime (fn:substring (fn:string ($utc-time), 1, 19) || "Z"); $orig-time, $utc-time, $adjusted-time It feels a bit wrong to serialize an xs:dateTime to xs:string to truncate the fractional seconds. It would be better to be able to apply the fn:floor function to the seconds part. But there isn't an xs:dateTime constructor that takes the individual year, month, etc values, so you can only manipulate the string representation to make changes. --- Ron Hitchens {mailto:[email protected]} Ronsoft Technologies +44 7879 358 212 (voice) http://www.ronsoft.com +1 707 924 3878 (fax) Bit Twiddling At Its Finest "No amount of belief establishes any fact." -Unknown On May 11, 2013, at 6:41 PM, David Lee <[email protected]> wrote: > toss in an fn:replace() to strip off the fractional seconds, or you can use > format-dateTime() on the adjusted time, > but dont have it put a timezone on just concatentate the "Z" > or you can construct the string yourself by extracting out all the values and > concatenating them or > recreate a dateTime with no fractional seconds. > Lots of ways to skin the cat. > > > ----------------------------------------------------------------------------- > David Lee > Lead Engineer > MarkLogic Corporation > [email protected] > Phone: +1 812-482-5224 > Cell: +1 812-630-7622 > www.marklogic.com > > > From: [email protected] > [mailto:[email protected]] On Behalf Of > [email protected] > Sent: Saturday, May 11, 2013 1:07 PM > To: MarkLogic Developer Discussion > Subject: Re: [MarkLogic Dev General] return current dateTime in UTC format > > Ellis, > > Thanks, that's close. > > fn:adjust-dateTime-to-timezone(current-dateTime(),xs:dayTimeDuration('PT0H')) > > returns: > 2013-05-11T17:01:18.209498Z > > I need this: > 2013-05-11T17:01:18Z > > Morgan > > From: "Ellis Pritchard" <[email protected]> > To: "MarkLogic Developer Discussion" <[email protected]> > Sent: Saturday, May 11, 2013 12:21:06 PM > Subject: Re: [MarkLogic Dev General] return current dateTime in UTC format > > fn:adjust-dateTime-to-timezone($dateTime,xs:dayTimeDuration('PT0H')) > > Ellis. > > On 11 May 2013, at 15:52, [email protected] wrote: > > The current-dateTime() function returns the following: > > 2013-05-11T10:38:45.333548-04:00 > > I need to have it expressed in UTC (Coordinated Universal Time), with a > special UTC designator ("Z") like: > > 1994-11-05T13:15:30Z > > How is that done? With format-dateTime()? > > Thanks, > Morgan > _______________________________________________ > > General mailing list > [email protected] > http://developer.marklogic.com/mailman/listinfo/general > > _______________________________________________ > General mailing list > [email protected] > http://developer.marklogic.com/mailman/listinfo/general > _______________________________________________ > General mailing list > [email protected] > http://developer.marklogic.com/mailman/listinfo/general _______________________________________________ General mailing list [email protected] http://developer.marklogic.com/mailman/listinfo/general
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