How about this?
$doc/b[c eq ("kind", "auto") and c/@xml:lang eq "nl"]/@id/fn:string()
From: Frank Mortier <[email protected]<mailto:[email protected]>>
Reply-To: MarkLogic Developer Discussion
<[email protected]<mailto:[email protected]>>
Date: Monday, 8 December 2014 18:01
To: MarkLogic Developer Discussion
<[email protected]<mailto:[email protected]>>
Subject: Re: [MarkLogic Dev General] Marklogic node replace of same node
results in inconsistent output
Given the following doc:
let $doc :=
<a>
<b id="car">
<c xml:lang="en">car</c>
<c xml:lang="nl">auto</c>
<c xml:lang="fr">voiture</c>
</b>
<b id="house">
<c xml:lang="en">house</c>
<c xml:lang="nl">huis</c>
<c xml:lang="fr">maison</c>
</b>
<b id= "child">
<c xml:lang="en">child</c>
<c xml:lang="nl">kind</c>
<c xml:lang="fr">enfant</c>
</b>
</a>
…….
And the following string (‘kind, car’), and language code (‘nl’), I would
like to retrieve the id attribute values.
I am looking for a simple flowr but do not seem to understand why the following
is not working.
for $x in $doc/b/c[@xml:lang eq"nl"]
where $x eq fn:tokenize('auto, kind', ',')
return
$x/../@value
Only gives the ‘id‘ whereas (‘auto’, ‘kind’) as in $x eq (‘auto’, ‘kind’) works?
Any suggestions would be welcome.
Frank
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