Thanks
Danny, I need to get from the string ('auto, kind') to ('auto', 'kind').
Chris, it should return 'car' and 'child'.
Tim, does not work, returns only the first id 'car'
Rob, same answer as for Danny.
-----Original Message-----
From: [email protected]
[mailto:[email protected]] On Behalf Of Danny Sokolsky
Sent: 08 December 2014 19:15
To: MarkLogic Developer Discussion
Subject: Re: [MarkLogic Dev General] Marklogic node replace of same node
results in inconsistent output
Hi Frank,
Or how about if you do a language-sensitive search. For example:
let $doc :=
<a>
<b id="car">
<c xml:lang="en">car</c>
<c xml:lang="nl">auto</c>
<c xml:lang="fr">voiture</c>
</b>
<b id="house">
<c xml:lang="en">house</c>
<c xml:lang="nl">huis</c>
<c xml:lang="fr">maison</c>
</b>
<b id= "child">
<c xml:lang="en">child</c>
<c xml:lang="nl">kind</c>
<c xml:lang="fr">enfant</c>
</b>
</a>
return $doc//c[cts:contains(., cts:or-query((
cts:word-query("auto", "lang=nl"),
cts:word-query("kind", "lang=nl"))) )] => <c
xml:lang="nl">auto</c> <c xml:lang="nl">kind</c>
-Danny
-----Original Message-----
From: [email protected]
[mailto:[email protected]] On Behalf Of Christopher Hamlin
Sent: Monday, December 08, 2014 10:14 AM
To: MarkLogic Developer Discussion
Subject: Re: [MarkLogic Dev General] Marklogic node replace of same node
results in inconsistent output
Hi Frank,
Not exactly sure if it's what you want, but maybe helps you get closer:
for $x in $doc/b/c[@xml:lang eq"nl"]
where $x/fn:string() = fn:tokenize('auto, kind', ',')
return
$x/../@id/fn:string()
returns 'car'.
I changed it so it compares the string value of $x with a list of strings from
tokenize. Note that I'm using = instead of eq. That lets you use a sequence
compare. Also the return now returns the @id attribute node.
- Chris
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