Hi David,
Thanks for that it worked fine - my code is below.
FYI the <p> at the end of the .label line is required. It is a HTML
paragraph tag so we get the label in bold on the top a paragraph break with
the image underneath. Without it the image is immediately to the right of
the label text.
<div ex:role="lens" class="a-lens">
<b ex:content=".label"></b><p>
<img ex:if-exists=".image" ex:src-content=".image" />
<p ex:content=".description"></p>
<i ex:content=".name"></i><br>
Start: <i ex:content=".start"></i><br>
End: <i ex:content=".end"></i>
</div>
Maybe using <br><br> instead of the <p> would be a little cleaner. That
works and does the same think probably more reliably.
Cheers and thanks for the response
Peter
-----Original Message-----
From: David Huynh [mailto:[EMAIL PROTECTED]
Sent: Tuesday, 26 February 2008 11:11 PM
To: [EMAIL PROTECTED]; General List
Subject: Re: Suppressing 'broken link' image in Exhibit
>You can change
<img ex:src-content=".image"><p>
to
<img ex:if-exists=".image" ex:src-content=".image" />
Or if Google Spreadsheets returns empty strings for empty cells, then
you can test it with ex:if
<img ex:if=".image <> ''" ex:src-content=".image" />
(That's a pair of single quotes.)
By the way, watch out for non-matching closing tags. The line
<b ex:content=".label"></b><p>
should not have <p> at the end.
David
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