Hello Marc,

Using the tools at UCSC, the Table Browser will return blocks of Conservation 
MAF results, but not specific bases. However, by sending the data over to 
Galaxy, "slices" of the Conservation track's MAF alignment can be retrieved in 
batch using a custom track of intervals (down to a single base). 

To do this:

1) Create and load a custom track in BED format of the genome positions of 
interest
2) Send the custom track to Galaxy by extracting it from the Table browser and 
checking Galaxy as the output choice
3) Send of the Conservation track's MAF alignment data to Galaxy using same 
method (you may need to subset this by chromosome to improve speed/performance)
3) Use the Galaxy tools: Fetch Alignments -> Extract MAF blocks given a set of 
genomic intervals

UCSC help is as follows:

http://genome.ucsc.edu/goldenPath/help/hgTracksHelp.html#CustomTracks
http://genome.ucsc.edu/goldenPath/help/hgTracksHelp.html#TableBrowser
http://genome.ucsc.edu/FAQ/FAQformat#format1
http://genomewiki.ucsc.edu/index.php/Coordinate_Transforms

Galaxy help is available at their web site if you have questions about the 
tools. 

Thanks,
Jennifer


------------------------------------------------ 
Jennifer Jackson 
UCSC Genome Bioinformatics Group 

----- "Marc Yao" <[email protected]> wrote:

> From: "Marc Yao" <[email protected]>
> To: [email protected]
> Sent: Sunday, January 10, 2010 8:09:23 AM GMT -08:00 US/Canada Pacific
> Subject: [Genome] How to get corresponding bases in multiz alignment in a 
> high-throughput way?
>
> Dear Sir or Madam,
> 
> I am working on the conservation between mouse genome and other
> mammalian genomes. I wonder how I can extract corresponding target
> genome sequences given mouse coordination as a query. For example, the
> 30-way multiz alignment track in genome browser shows 'C' is at
> chr4:139,328,937 in mouse genome and the corresponding base in rat
> genome is 'T' and in human genome is 'G'. I have scores of thousands
> of such queries need to make. Is there a way (or script/code) to do
> this in a high-throughput way?
> 
> Thanks,
> 
> Marc
> 
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