Hello Anna,

You can get UCSC Genes exon coordinates for your LocusLink (a.k.a. 
Entrez Gene) identifiers using the Table Browser 
(http://genome.ucsc.edu/cgi-bin/hgTables).  Select the following options:

clade: Mammal
genome: Human
assembly: Feb. 2009 (GRCh37/hg19)
group: Genes and Gene Prediction Tracks
track: UCSC Genes
table: knownGene
region: genome

Now hit "filter: create."  Under "Linked Tables," select the 
knownToLocusLink table and hit the "Allow Filtering Using Fields in 
Checked Tables" button.  In the hg19.knownToLocusLink based filters 
section, paste your list of identifiers in the "value does match" box 
and hit submit.  (The box is small, but it will accept a list of 
identifiers.)

Now choose "output format: selected fields from primary and related 
tables" and hit "get output."  From knownGene, select chrom, strand, 
exonStarts, and exonEnds, and any other fields you would like to see in 
the output.  Then scroll down and select the knownToLocusLink table 
again and hit "Allow Selection from Checked Tables."  Check the box next 
to "value" to see your LocusLink identifier in the output.

Hit "get output."  The result should be the exon coordinates for the 
gene identifiers that you entered.

It's possible to do something similar to get RefSeq Gene exon 
coordinates if you prefer, but you would need to first convert the 
LocusLink identifiers to RefSeq Gene identifiers (using either the Table 
Browser and the refLink table or an online conversion tool such as 
DAVID: http://david.abcc.ncifcrf.gov/conversion2.jsp).  You would then 
select RefSeq Genes in the Table Browser and enter the list of 
identifiers in the "identifiers (names/accessions): paste list" section.

If you have further questions, please contact us again at 
[email protected].

--
Brooke Rhead
UCSC Genome Bioinformatics Group


On 4/12/12 2:48 PM, [email protected] wrote:
>
> Hi,
>
> Does anyone know how to get the exon coordinates of a set of human genes if 
> you have the
> LocusLink ID of these genes?  Thanks in advance for any help.
>
> Anna
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