Hello all,
given the following case
-- file entity_foo.vhd
entity foo is
port(a,b:in bit; z: out bit);
end;
-- file arch_foo1.vhd
architecture foo1 of foo is
begin
z <= a xor b;
end;
-- file arch_foo2.vhd
architecture foo1 of foo is
begin
process begin
wait on a,b;
z <= a xor b;
end process;
end;
I do compile them into lib_foo with
ghdl -a --work=lib_foo entity_foo.vhd
ghdl -a --work=lib_foo arch_foo1.vhd
ghdl -a --work=lib_foo arch_foo2.vhd
when I use this entity from other file
-- file user.vhd
entity main is end;
architecture main of main is
signal x,y,z: bit;
begin
foo1: entity foo port map(a=>x,b=>y,z=>z);
end;
which architecture is actually used?
would the sequence of analizing the architectures
change the choice?
ghdl -a --work=lib_foo arch_foo2.vhd
ghdl -a --work=lib_foo arch_foo1.vhd
what if I place those two architectures into one file
which one would be taken then for default?
is the default architecture choice tool specific behaviour?
Thanks in advance
Regards, Daniel
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