Eric Sunshine <> writes:

> On Sun, Jun 9, 2013 at 2:25 AM, Nguyễn Thái Ngọc Duy <> 
> wrote:
>> The function is made to use with free_pathspec() because a simple
>> struct assignment is not enough (free_pathspec wants to free "items"
>> pointer).
> I had to read this about five or six times before I could parse and
> understand it. Perhaps rewrite something like this:
>     free_pathspec() frees pathspec->items, hence simple struct
>     assignment does not properly duplicate a pathspec. Introduce
>     copy_pathspec() to clone a pathspec correctly by deeply copying
>     the items member.

Thanks.  It might be worth that this is not a full "deep" copy,
perhaps like this:

    pathspec: add copy_pathspec
    Because free_pathspec wants to free "items" pointer in the pathspec
    structure, a simple structure assignment is not enough if you want
    to copy an existing pathspec into another.  Freeing the original will
    damage the copy unless a deep copy is made.
    Note that the strings in pathspec->items->match and the array
    pathspec->raw[] are still shared between the original and the
    Signed-off-by: Nguyễn Thái Ngọc Duy <>
    Signed-off-by: Junio C Hamano <>
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