"Kyle J. McKay" <mack...@gmail.com> writes:

> Instead, we can use the [...] construct to defeat the special meaning
> of the '?' character and match it exactly in a way that works for the
> FreeBSD /bin/sh as well as other POSIX /bin/sh implementations.
> Changing the example like so:
> x='one?two?three'
> echo "${x#*[?]}"
> Produces the expected output using the FreeBSD /bin/sh.

I'll queue this in the meantime, while 1&2/3 are sorted out between
you and Matthieu.

I will also take "cp -a" patch with "-R -P -p", not just "-R" for
the reasons stated in the other thread.

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