> parenthesized initializers are highlighted and they probably should not
@b4n, Good catch, another place the syntax is used for something else, ahh C++
> operators is not highlighted as functions.
@linvinus I'm not sure you understood the point, in C++ the call operator ()
can be overloaded and applied to objects, not just to functions. Your image
doesn't show that case. As @b4n says it depends if you want all callables
highlighted, or functions.
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