> parenthesized initializers are highlighted and they probably should not 

@b4n, Good catch, another place the syntax is used for something else, ahh C++ 
:)

> operators is not highlighted as functions.

@linvinus I'm not sure you understood the point, in C++ the call operator () 
can be overloaded and applied to objects, not just to functions.  Your image 
doesn't show that case.  As @b4n says it depends if you want all callables 
highlighted, or functions.  

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