> parenthesized initializers are highlighted and they probably should not
@b4n, Good catch, another place the syntax is used for something else, ahh C++ :) > operators is not highlighted as functions. @linvinus I'm not sure you understood the point, in C++ the call operator () can be overloaded and applied to objects, not just to functions. Your image doesn't show that case. As @b4n says it depends if you want all callables highlighted, or functions. -- You are receiving this because you are subscribed to this thread. Reply to this email directly or view it on GitHub: https://github.com/geany/geany/issues/1231#issuecomment-247302976
