Thanks everyone so much for the wealth of info!

Chalo, you mentioned that the width of one lens plus the center width
should equal the interpupillary distance (PD).  I assume that by
"center width" you mean half of the bridge width?  If so, the lens
width of the frame I've (mostly) decided upon at Zenni is 50mm + the
bridge 18mm / 2 = 59mm.  My PD is 59.5 distance & 54.5 near, so this
lens does sound like a slightly better fit than my current lens, which
is 53mm.

For whatever it's worth, I think I just have a little larger face
overall than some.  My current frames are 142mm total width and fit
very well.  So, my PD of 59mm may be just a smidge narrow for my face
size proportionately.  My pupils don't land (horizontally) in the
middle of the lens of my current glasses, but as you suspected,
instead fall just a bit inboard of that.  So that may be what
contributes to the extra edge thickness on that left lens.  I'm
betting that, like your sister, the brick & mortar shop charged me for
a grade of lens that I didn't get.

Using the calculator you linked to (Thanks, Chuck!!) on the lens shape
that I've selected my findings are in line with yours, Eric - that the
stronger left lens should be just about 4mm thick at the outer edge.
Given that my current lens is a hair less than 6mm on that outer edge,
I think I can live with that.

Again, I really appreciate the info, guys!

Rob
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