You wrote:
>The area of sunshade in orbit needed to remove the current
>global warming is, therefore roughly .002 * 125,000,000 km squared
>or 300000 km squared.
>
>If your sunshades were one 10,000th of a meter thick and made of
>Aluminum, you would need to orbit 30 km cubed worth of Aluminum.
>
>The density of Aluminum is 2.70 g/cm³.
>
>One km cubed is equal to 10 to the 15 cm cubed.
>
>So you want to orbit 8 times 10 to the 13 the power kg of Aluminum.
You didn't check your units. I did the same thing the first time I
tried it.
I followed you to the 30,000 km sq, but then your 1/10,000 m
multiplicaton should have been 1/10,000,000 km, thus the volume of
aluminum would be 0.03 km^3 or 3.0 * 10^13 cm^3, thus the mass would be
8.1*10^13 g or 8.1*10^10 kg.
This is 81 million metric tons, still a very large quantity, to be
sure.
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