reflect/* is a bit tricky. Use pointer to get interface itself.
package main
import (
"fmt"
"reflect"
)
func main() {
test := interface{}("test")
printInterfaceValue(test)
}
func printInterfaceValue(i interface{}) {
switch testing := i.(type) {
case interface{}:
fmt.Println("is interface, with value:", testing)
case string:
fmt.Println("is not interface")
}
fmt.Println("reflect.Type is", reflect.TypeOf(&i).Elem())
}
Output:
is interface, with value: test
reflect.Type is interface {}
понедельник, 10 декабря 2018 г., 5:05:12 UTC+3 пользователь Robert Engels
написал:
>
> I mean reflect.Type not a type that is an interface.
>
> On Dec 9, 2018, at 6:53 PM, Space A. <reexi...@gmail.com <javascript:>>
> wrote:
>
> Of course. When you "pass a value whose type implements the interface" as
> an interface argument to a function, you in fact pass an *interface*.
>
>
> воскресенье, 9 декабря 2018 г., 23:23:41 UTC+3 пользователь Mark Volkmann
> написал:
>>
>> Is it possible to pass an interface to a function in Go? I don’t want to
>> pass a value whose type implements the interface, I want to pass the
>> interface.
>>
>> --
>> R. Mark Volkmann
>> Object Computing, Inc.
>>
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