Yes, this is what I'm trying to do!
Perhaps this is not possible.
On Sun, Dec 9, 2018 at 10:34 PM Robert Engels <reng...@ix.netcom.com> wrote:
> I think what the OP wants is:
>
> type A interface{}
> type B interface{}
>
> ...
> PrintInterface(A)
>
> Meaning they want to pass the interface definition to some method.
>
> At least that’s what I am guessing.
>
> On Dec 9, 2018, at 9:22 PM, Space A. <reexist...@gmail.com> wrote:
>
> reflect/* is a bit tricky. Use pointer to get interface itself.
>
> package main
>
> import (
> "fmt"
> "reflect"
> )
>
> func main() {
> test := interface{}("test")
> printInterfaceValue(test)
> }
>
> func printInterfaceValue(i interface{}) {
> switch testing := i.(type) {
> case interface{}:
> fmt.Println("is interface, with value:", testing)
> case string:
> fmt.Println("is not interface")
> }
>
> fmt.Println("reflect.Type is", reflect.TypeOf(&i).Elem())
> }
>
> Output:
>
> is interface, with value: test
> reflect.Type is interface {}
>
>
>
>
>
>
> понедельник, 10 декабря 2018 г., 5:05:12 UTC+3 пользователь Robert Engels
> написал:
>>
>> I mean reflect.Type not a type that is an interface.
>>
>> On Dec 9, 2018, at 6:53 PM, Space A. <reexi...@gmail.com> wrote:
>>
>> Of course. When you "pass a value whose type implements the interface" as
>> an interface argument to a function, you in fact pass an *interface*.
>>
>>
>> воскресенье, 9 декабря 2018 г., 23:23:41 UTC+3 пользователь Mark Volkmann
>> написал:
>>>
>>> Is it possible to pass an interface to a function in Go? I don’t want to
>>> pass a value whose type implements the interface, I want to pass the
>>> interface.
>>>
>>> --
>>> R. Mark Volkmann
>>> Object Computing, Inc.
>>>
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--
R. Mark Volkmann
Object Computing, Inc.
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