thanks! v must be a value copy，Is this determined by the compiler?
在 2019年4月3日星期三 UTC+8下午7:57:26，Marvin Renich写道：
>
> * mount...@gmail.com <javascript:> <mount...@gmail.com <javascript:>>
> [190403 05:10]:
> > package main
> >
> > func main() {
> > b := []int{1}
> >
> > bb := make([]*int, 0, 1)
> > for k, v := range b {
>
> The above range clause will assign to k the index of the current
> element, and it will assign to v a copy (as if v = b[k]) of the element
> at that index.
>
> Go does not have references of the kind that C++ or Java has, so v
> cannot be a reference, in that sense, to b[k]; it must be a value copy.
>
> If what you really want is to be able to refer to the location of the
> element in the slice (really its backing array), omit the v in the range
> clause and just use &b[k]:
>
> for k := range b {
> _ = &b[k] // do what you want
> }
>
> > _ = &v //8 line
> > _ = &b[k] //9 line
> > // bb = append(bb, &v)
> > bb = append(bb, &b[k])
> > }
> >
> > // for _, v := range bb {
> > // fmt.Println(*v)
> > // }
> > }
>
> ...Marvin
>
>
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