On Wed, Apr 3, 2019 at 6:32 AM <mountain...@gmail.com> wrote:
>
> thanks! v must be a value copy，Is this determined by the compiler?
It's determined by the language definition.
Ian
> 在 2019年4月3日星期三 UTC+8下午7:57:26，Marvin Renich写道：
>>
>> * mount...@gmail.com <mount...@gmail.com> [190403 05:10]:
>> > package main
>> >
>> > func main() {
>> > b := []int{1}
>> >
>> > bb := make([]*int, 0, 1)
>> > for k, v := range b {
>>
>> The above range clause will assign to k the index of the current
>> element, and it will assign to v a copy (as if v = b[k]) of the element
>> at that index.
>>
>> Go does not have references of the kind that C++ or Java has, so v
>> cannot be a reference, in that sense, to b[k]; it must be a value copy.
>>
>> If what you really want is to be able to refer to the location of the
>> element in the slice (really its backing array), omit the v in the range
>> clause and just use &b[k]:
>>
>> for k := range b {
>> _ = &b[k] // do what you want
>> }
>>
>> > _ = &v //8 line
>> > _ = &b[k] //9 line
>> > // bb = append(bb, &v)
>> > bb = append(bb, &b[k])
>> > }
>> >
>> > // for _, v := range bb {
>> > // fmt.Println(*v)
>> > // }
>> > }
>>
>> ...Marvin
>>
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