Hello, Ive tried to switch this over to use getElementsByTagNameNS but the number of entries always comes up as 0 but when I use the simple implementation I get my 6 items;
var items = google.feeds.getElementsByTagNameNS(result.xmlDocument, "http://search.yahoo.com/mrss/";, "item"); returns an items.length=0 var items = result.xmlDocument.getElementsByTagName('item'); gives items.length=6 for feed(as Ive requested only 6 items; http://publish.vx.roo.com/g6publish/common/playlist/rssgeneratorportal.aspx?SiteId=cb519624-44a2-4bf7-808b-3514d34e96e4&Format=flash&v=3&thumbnailtypecode=wide_small&channel=Latest+Videos&rsstype=mrss Is this feed format supported? Regards, BjP On Mar 24, 1:14 pm, BjP <[email protected]> wrote: > Thanks Jeremy, I'll give this a shot with the > getElementsByTagNameNS. Was looking at this earlier and wasnt sure if > I needed it or not. > > Kind Regards, > BjP > > On Mar 23, 9:43 pm, Jeremy Geerdes <[email protected]> wrote: > > > Instead of getElementsByTagName('media:thumbnail'), you need to use > > getElementsByTagNameNS(). The reason for this is that the tagName for > > the element you're looking for is really just "thumbnail." "media" > > represents the namespace in which the browser will find the tag's > > definition. For the sake of cross-browser compatibility, you'll > > probably want to use the getElementsByTagNameNS included in the Feeds > > API. Its usage is outlined in the documentation at the link below: > > >http://code.google.com/apis/ajaxfeeds/documentation/reference.html#ge... > > > Jeremy R. Geerdes > > Effective website design & development > > Des Moines, IA > > > For more information or a project > > quote:http://jgeerdes.home.mchsi.comhttp://jgeerdes.blogspot.comhttp://jgee... > > [email protected] > > > Unless otherwise noted, any price quotes contained within this > > communication are given in US dollars. > > > If you're in the Des Moines, IA, area, check out Debra Heights > > Wesleyan Church! > > > And check out my blog, Adventures in Web Development, > > athttp://jgeerdes.blogspot.com > > ! > > > On Mar 23, 2009, at 12:35 AM, BjP wrote: > > > > Hello, > > > > Im adapting a MRSS feed to display some of the latest videos added to > > > the feed on my company sites; > > > >http://publish.vx.roo.com/g6publish/common/playlist/rssgeneratorporta... > > > > The code Ive constructed has been a simple copy of one of the XML > > > examples with some simple additions of jquery to render the result. > > > > However Ive found that in Firefox 2 and also Chrome I am unable to get > > > the url attribute value of the media:thumbnail node with the error > > > > item.getElementsByTagName("media:thumbnail")[0] has no properties > > > > appearing in Firebug. > > > > The code I am using for the feedloaded section; > > > > function feedLoaded(result) { > > > if (!result.error) { > > > // Get all items returned. > > > var items = result.xmlDocument.getElementsByTagName('item'); > > > //clear out results div. > > > $(".video<%inf_pageid%>").empty(); > > > $(".video<%inf_pageid%>").append('<h3>Latest Videos</h3>'); > > > // Loop through our items > > > for (var i = 0; i < items.length; i++) { > > > var item = items[i]; > > > // Get the title from the element. firstChild is the text node > > > containing > > > // the title, and nodeValue returns the value of it. > > > var title = item.getElementsByTagName("title") > > > [0].firstChild.nodeValue; > > > var link = item.getElementsByTagName("link") > > > [0].firstChild.nodeValue; > > > var descript= item.getElementsByTagName("description") > > > [0].firstChild.nodeValue; > > > //var temp= item.getElementsByTagName("media:thumbnail")[0]; > > > //alert(temp); > > > //var thumb = temp.attributes.getNamedItem("url").value; > > > var thumb = item.getElementsByTagName("media:thumbnail") > > > [0].getAttribute("url"); > > > //alert(ff2); > > > //create html string of complete listing > > > var html = '<div class="item"><div class="preview-image"><a > > > title="' + title + '" href="'+ link + '"><img alt="' + title + ' > > > image" width="128" height="72" src="' + thumb + '"/></a></div><h4 > > > width="20"><a title="' + title + '" href="' + link + '">' + title + > > > '</ > > > a></h4><div class="text">' + descript + '</div></div>'; > > > //clear and append the output of string to video div > > > $(".video<%inf_pageid%>").append(html); > > > } > > > } > > > } > > > > Any ideas why this doesnt work in FF2 or Chrome? > > > > Thanks in advance, > > > BjP --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Google AJAX APIs" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/Google-AJAX-Search-API?hl=en -~----------~----~----~----~------~----~------~--~---
