Hi Jeremy, Just removing the media: from the start of the node name did the trick as i iterate through each item;
var thumbelement = google.feeds.getElementsByTagNameNS(item, "http:// search.yahoo.com/mrss/", "thumbnail")[0]; Thanks for your help! Cheers, BjP On Mar 24, 9:58 pm, Jeremy Geerdes <[email protected]> wrote: > The item element is not a part of the media namespace, so > getElementsByTagNameNS won't return it when you try to find it there. > Try using getElementsByTagName for the tags that don't have media: in > front of their names, and getElementsByTagNameNS for the ones that do. > > Jeremy R. Geerdes > Effective website design & development > Des Moines, IA > > For more information or a project > quote:http://jgeerdes.home.mchsi.comhttp://jgeerdes.blogspot.comhttp://jgeerdes.wordpress.com > [email protected] > > Unless otherwise noted, any price quotes contained within this > communication are given in US dollars. > > If you're in the Des Moines, IA, area, check out Debra Heights > Wesleyan Church! > > And check out my blog, Adventures in Web Development, > athttp://jgeerdes.blogspot.com > ! > > On Mar 23, 2009, at 11:25 PM, BjP wrote: > > > > > Hello, > > > Ive tried to switch this over to use getElementsByTagNameNS but the > > number of entries always comes up as 0 but when I use the simple > > implementation I get my 6 items; > > > var items = google.feeds.getElementsByTagNameNS(result.xmlDocument, > > "http://search.yahoo.com/mrss/";, "item"); > > > returns an items.length=0 > > > var items = result.xmlDocument.getElementsByTagName('item'); > > > gives items.length=6 for feed(as Ive requested only 6 items; > > >http://publish.vx.roo.com/g6publish/common/playlist/rssgeneratorporta... > > > Is this feed format supported? > > > Regards, > > BjP > > > On Mar 24, 1:14 pm, BjP <[email protected]> wrote: > >> Thanks Jeremy, I'll give this a shot with the > >> getElementsByTagNameNS. Was looking at this earlier and wasnt sure > >> if > >> I needed it or not. > > >> Kind Regards, > >> BjP > > >> On Mar 23, 9:43 pm, Jeremy Geerdes <[email protected]> wrote: > > >>> Instead of getElementsByTagName('media:thumbnail'), you need to use > >>> getElementsByTagNameNS(). The reason for this is that the tagName > >>> for > >>> the element you're looking for is really just "thumbnail." "media" > >>> represents the namespace in which the browser will find the tag's > >>> definition. For the sake of cross-browser compatibility, you'll > >>> probably want to use the getElementsByTagNameNS included in the > >>> Feeds > >>> API. Its usage is outlined in the documentation at the link below: > > >>>http://code.google.com/apis/ajaxfeeds/documentation/reference.html#ge > >>> ... > > >>> Jeremy R. Geerdes > >>> Effective website design & development > >>> Des Moines, IA > > >>> For more information or a project quote:http://jgeerdes.home.mchsi.comhttp > >>> ://jgeerdes.blogspot.comhttp://jgee... > >>> [email protected] > > >>> Unless otherwise noted, any price quotes contained within this > >>> communication are given in US dollars. > > >>> If you're in the Des Moines, IA, area, check out Debra Heights > >>> Wesleyan Church! > > >>> And check out my blog, Adventures in Web Development, > >>> athttp://jgeerdes.blogspot.com > >>> ! > > >>> On Mar 23, 2009, at 12:35 AM, BjP wrote: > > >>>> Hello, > > >>>> Im adapting a MRSS feed to display some of the latest videos > >>>> added to > >>>> the feed on my company sites; > > >>>>http://publish.vx.roo.com/g6publish/common/playlist/rssgeneratorporta > >>>> ... > > >>>> The code Ive constructed has been a simple copy of one of the XML > >>>> examples with some simple additions of jquery to render the result. > > >>>> However Ive found that in Firefox 2 and also Chrome I am unable > >>>> to get > >>>> the url attribute value of the media:thumbnail node with the error > > >>>> item.getElementsByTagName("media:thumbnail")[0] has no properties > > >>>> appearing in Firebug. > > >>>> The code I am using for the feedloaded section; > > >>>> function feedLoaded(result) { > >>>> if (!result.error) { > >>>> // Get all items returned. > >>>> var items = result.xmlDocument.getElementsByTagName('item'); > >>>> //clear out results div. > >>>> $(".video<%inf_pageid%>").empty(); > >>>> $(".video<%inf_pageid%>").append('<h3>Latest Videos</h3>'); > >>>> // Loop through our items > >>>> for (var i = 0; i < items.length; i++) { > >>>> var item = items[i]; > >>>> // Get the title from the element. firstChild is the text > >>>> node > >>>> containing > >>>> // the title, and nodeValue returns the value of it. > >>>> var title = item.getElementsByTagName("title") > >>>> [0].firstChild.nodeValue; > >>>> var link = item.getElementsByTagName("link") > >>>> [0].firstChild.nodeValue; > >>>> var descript= item.getElementsByTagName("description") > >>>> [0].firstChild.nodeValue; > >>>> //var temp= item.getElementsByTagName("media:thumbnail")[0]; > >>>> //alert(temp); > >>>> //var thumb = temp.attributes.getNamedItem("url").value; > >>>> var thumb = item.getElementsByTagName("media:thumbnail") > >>>> [0].getAttribute("url"); > >>>> //alert(ff2); > >>>> //create html string of complete listing > >>>> var html = '<div class="item"><div class="preview-image"><a > >>>> title="' + title + '" href="'+ link + '"><img alt="' + title + ' > >>>> image" width="128" height="72" src="' + thumb + '"/></a></div><h4 > >>>> width="20"><a title="' + title + '" href="' + link + '">' + title + > >>>> '</ > >>>> a></h4><div class="text">' + descript + '</div></div>'; > >>>> //clear and append the output of string to video div > >>>> $(".video<%inf_pageid%>").append(html); > >>>> } > >>>> } > >>>> } > > >>>> Any ideas why this doesnt work in FF2 or Chrome? > > >>>> Thanks in advance, > >>>> BjP --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Google AJAX APIs" group. 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