Depends on your programming language. In python it would be:
a = 1
k = 1
while (k <= 500):
 a *= k
 k += 1
print a


On Sun, May 23, 2010 at 9:24 AM, Bharath Raghavendran
<[email protected]> wrote:
> you can calculate nCr using a dynamic programming type algo as nCr = n-1Cr +
> n-1Cr-1.
> calculate for largest possible n once .. and once thats done, getting this
> value would be O(1). Calculating factorial of 500 looks scary
>
> On 23 May 2010 13:49, Mikhail Dektyarev <[email protected]>
> wrote:
>>
>> As I know, dict uses trees, not hashes.
>> And to find the right size is not difficult. 501x501 will be enough,
>> filling with 0 by default.
>>
>> On Sun, May 23, 2010 at 12:17 PM, Atanas Banov <[email protected]> wrote:
>>>
>>> errr, no. hash lookup is O(1), not log... you are thinking balanced trees
>>> or some such.
>>> also while 2D array will be a bit faster, you will have to deal with
>>> proper sizing and filling default value.
>>>
>>> On Sat, May 22, 2010 at 8:18 PM, Terence <[email protected]> wrote:
>>>>
>>>> Another point is to use array (2-D list) instead of dict to implement
>>>> cache. this will reduce the time complexity of cache lookup operation from
>>>> O(logN) to O(1)
>>>>
>>>
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>>
>>
>> --
>> Best regards, Дектярев Михаил
>>
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