I have the same problem and I disagree with this comment. I am modding
all values by 100003, however, there was one multiplication at a point
in the code that I overlooked. Given x, y < 100003, the product x * y
could potentially reach 10 ^ 10 and exceed the 32-bit unsigned integer
limit, which is just above 4 * 10 ^ 9. Hence, casting to 64 bit
integer is necessary.

On May 24, 7:51 am, Bharath Balakrishnan <[email protected]>
wrote:
> Your output was modulo 100003. A carefully coded program with mod (%) in the
> right places would have worked with int itself. You don't need a long.
>
>
>
> On Sun, May 23, 2010 at 1:11 AM, bokertov <[email protected]> wrote:
> > I used "int" and it worked for the small case. But my output for the
> > large case was incorrect. Then I found out if I replace "int" by "long
> > long", then it's correct! I lost 30 points because of this stupid
> > mistake, man!
>
> > The reason is that 10^5*10^5 = 10^10, which is bigger than the upper
> > bound ~ 2*10^9 of int.
>
> > I'll surely learn this lesson, and will avoid it in the future.
>
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> --
> Regards,
> Bharath B
>
> "When the going gets tough, the tough get going"
>
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