why did google choose 100003 and not some nice looking number like 100000 ?
:P

On 26 May 2010 03:54, mtsay <[email protected]> wrote:

> I have the same problem and I disagree with this comment. I am modding
> all values by 100003, however, there was one multiplication at a point
> in the code that I overlooked. Given x, y < 100003, the product x * y
> could potentially reach 10 ^ 10 and exceed the 32-bit unsigned integer
> limit, which is just above 4 * 10 ^ 9. Hence, casting to 64 bit
> integer is necessary.
>
> On May 24, 7:51 am, Bharath Balakrishnan <[email protected]>
> wrote:
> > Your output was modulo 100003. A carefully coded program with mod (%) in
> the
> > right places would have worked with int itself. You don't need a long.
> >
> >
> >
> > On Sun, May 23, 2010 at 1:11 AM, bokertov <[email protected]> wrote:
> > > I used "int" and it worked for the small case. But my output for the
> > > large case was incorrect. Then I found out if I replace "int" by "long
> > > long", then it's correct! I lost 30 points because of this stupid
> > > mistake, man!
> >
> > > The reason is that 10^5*10^5 = 10^10, which is bigger than the upper
> > > bound ~ 2*10^9 of int.
> >
> > > I'll surely learn this lesson, and will avoid it in the future.
> >
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> > --
> > Regards,
> > Bharath B
> >
> > "When the going gets tough, the tough get going"
> >
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