Indeed the solution mentioned on
http://code.google.com/codejam/contest/dashboard?c=32016#s=a&a=2 is
pretty awesome but that lays stress on mathematical concepts over
advanced programming logic.... which means that we have to be good
mathematicians first to be a good programmer...

Nah I dont agree....I have a different solution...

Rule 1: Square-roots can be calculated by division while division can
be done by multiplication... (moreover multiplication can be done by
addition but that wont be required here)

Rule 2: If seen from a different perspective each digit of the result
is calculated by a set pattern or simple terms a formula

P.S.: We just need to develop the formula for first and second digit
of the result for n (where n<=2000000000) in terms of multiplying or
adding the digits of the question

Comment: In this approach value of n or the max size of a variable
wont be a constraint. Not just this but any calculation can be done
up-to infinite limits, the only constraint shall be time and space.

Utsav



On Mon, Apr 18, 2011 at 9:52 PM, Luke Pebody <[email protected]> wrote:
> "You can't". You'd need a lot of memory and a lot of time to work out the
> integer part of this large a value. However, you don't need to work out the
> entire integer part. You can, for instance find the last two digits of
> 2301^45392884746345 without working out all of the digits. See the "Contest
> Analysis" at http://bit.ly/21iXp4
>
> On 18 Apr 2011 17:11, "raulrag" <[email protected]> wrote:
>> How will u handle such a large input of 2000000000 in C .
>> What different techniques can be used to find (3+root(5) ) ^N for such
>> a large input
>>
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