*Conjugate pairs* are the key.  Here's a detailed explanation...

http://www.necessaryandsufficient.net/2008/07/google-codejam-numbers/

Hope that helps.

On Tue, Apr 19, 2011 at 6:35 AM, utsav sabharwal <[email protected]>wrote:

> Indeed the solution mentioned on
> http://code.google.com/codejam/contest/dashboard?c=32016#s=a&a=2 is
> pretty awesome but that lays stress on mathematical concepts over
> advanced programming logic.... which means that we have to be good
> mathematicians first to be a good programmer...
>
> Nah I dont agree....I have a different solution...
>
> Rule 1: Square-roots can be calculated by division while division can
> be done by multiplication... (moreover multiplication can be done by
> addition but that wont be required here)
>
> Rule 2: If seen from a different perspective each digit of the result
> is calculated by a set pattern or simple terms a formula
>
> P.S.: We just need to develop the formula for first and second digit
> of the result for n (where n<=2000000000) in terms of multiplying or
> adding the digits of the question
>
> Comment: In this approach value of n or the max size of a variable
> wont be a constraint. Not just this but any calculation can be done
> up-to infinite limits, the only constraint shall be time and space.
>
> Utsav
>
>
>
> On Mon, Apr 18, 2011 at 9:52 PM, Luke Pebody <[email protected]>
> wrote:
> > "You can't". You'd need a lot of memory and a lot of time to work out the
> > integer part of this large a value. However, you don't need to work out
> the
> > entire integer part. You can, for instance find the last two digits of
> > 2301^45392884746345 without working out all of the digits. See the
> "Contest
> > Analysis" at http://bit.ly/21iXp4
> >
> > On 18 Apr 2011 17:11, "raulrag" <[email protected]> wrote:
> >> How will u handle such a large input of 2000000000 in C .
> >> What different techniques can be used to find (3+root(5) ) ^N for such
> >> a large input
> >>
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