XOR is the bread and butter of Symmetric Cryptography.
~mhb

On Mon, May 9, 2011 at 4:44 PM, Marcelo Ramires
<[email protected]> wrote:
> I understood how to solve this, but how does one come to this solution ?
>
> If the xor of all numbers is zero, you can pick any candy, and the xor to
> this number is going to be equal to the xor from the rest of them.
>
> I get this, if I have 9 numbers with XOR 3, XORing it with 3 will get me
> zero.
>
> How has everybody thought of this at the same time ? have I skipped a logics
> class ? is this concept so disseminated among coders ?
>
> I had never XORed nubmers before this code jam, only booleans, and I didn't
> know you could.
>
> As a side questions, can anybody tell me any alternative uses for XORing
> integers other than 1 and 0 ?
>
> Thanks!
>
> Marcelo Ramires
>
> On Sun, May 8, 2011 at 1:50 AM, vivek dhiman <[email protected]> wrote:
>>
>> Lucky!
>>
>> You are right.
>>
>> if xor of two lists is same. (say xor1 = xo2)
>>
>> So the exor of these two wil be 0  (xor (xor1,xor2) = 0)
>> Or in other words lists can be divided if the xor of all the elements is
>> zero.
>>
>> :)
>>
>>
>>
>> On Sun, May 8, 2011 at 8:17 AM, keshav agarwal <[email protected]>
>> wrote:
>>>
>>> please tell me of my logic was correct or i just got lucky to get it
>>> correct
>>>
>>> if xor to a list of nos. is zero only then the division is possible
>>> in this case patrick can be given the one candy with lowest value while
>>> sean keeps the rest
>>>
>>> if      xor(n nos.)=0
>>> then       (nth no.) xor (xor of n-1 nos.)=0
>>>
>>> so patrick gets the nth candy and sean keeps the rest
>>>
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>>
>>
>>
>> --
>> Regards
>> Vivek Dhiman
>>
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