Hi,
One could come to this solution by understanding the Sean adding skills,

  1100
+ 0101
------
  1001

compare this with the XOR truth table and you will have a match.
As others posted before practice will help us to see these patterns while
reading the problems.

(Personally I didn't use an explicit integer XOR, I used mod 2)


On Mon, May 9, 2011 at 4:59 PM, rahul raghavendra <[email protected]>wrote:

> u can do a lot of stuff with the bitwise operators , u just gotta
> experiment with it
>
>
> On Tue, May 10, 2011 at 2:21 AM, Morgan Bauer <[email protected]>wrote:
>
>> XOR is the bread and butter of Symmetric Cryptography.
>> ~mhb
>>
>> On Mon, May 9, 2011 at 4:44 PM, Marcelo Ramires
>> <[email protected]> wrote:
>> > I understood how to solve this, but how does one come to this solution ?
>> >
>> > If the xor of all numbers is zero, you can pick any candy, and the xor
>> to
>> > this number is going to be equal to the xor from the rest of them.
>> >
>> > I get this, if I have 9 numbers with XOR 3, XORing it with 3 will get me
>> > zero.
>> >
>> > How has everybody thought of this at the same time ? have I skipped a
>> logics
>> > class ? is this concept so disseminated among coders ?
>> >
>> > I had never XORed nubmers before this code jam, only booleans, and I
>> didn't
>> > know you could.
>> >
>> > As a side questions, can anybody tell me any alternative uses for XORing
>> > integers other than 1 and 0 ?
>> >
>> > Thanks!
>> >
>> > Marcelo Ramires
>> >
>> > On Sun, May 8, 2011 at 1:50 AM, vivek dhiman <[email protected]>
>> wrote:
>> >>
>> >> Lucky!
>> >>
>> >> You are right.
>> >>
>> >> if xor of two lists is same. (say xor1 = xo2)
>> >>
>> >> So the exor of these two wil be 0  (xor (xor1,xor2) = 0)
>> >> Or in other words lists can be divided if the xor of all the elements
>> is
>> >> zero.
>> >>
>> >> :)
>> >>
>> >>
>> >>
>> >> On Sun, May 8, 2011 at 8:17 AM, keshav agarwal <[email protected]>
>> >> wrote:
>> >>>
>> >>> please tell me of my logic was correct or i just got lucky to get it
>> >>> correct
>> >>>
>> >>> if xor to a list of nos. is zero only then the division is possible
>> >>> in this case patrick can be given the one candy with lowest value
>> while
>> >>> sean keeps the rest
>> >>>
>> >>> if      xor(n nos.)=0
>> >>> then       (nth no.) xor (xor of n-1 nos.)=0
>> >>>
>> >>> so patrick gets the nth candy and sean keeps the rest
>> >>>
>> >>> --
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>> >>
>> >>
>> >> --
>> >> Regards
>> >> Vivek Dhiman
>> >>
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> *
> K.Rahul  )
>
>
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-- 
Reniery

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