http://en.wikipedia.org/wiki/Catalan_number 



On 3 Apr 2012, at 03:35, vivek dhiman <[email protected]> wrote:

> Hi..
> 
> you are correct ...thanks.. it can be done using DP..
> and I did it :)
> On Tue, Apr 3, 2012 at 1:48 AM, Carlos Guia <[email protected]> 
> wrote:
> Do you have a constrain on k? It can be done in O(k^2).
> 
> Dp(p, k) would be the count the number of arrangements of size k of the 
> previous number was p. 
> The transitions aren't hard, there are at most three of them, you should be 
> able to figure them out.
> 
> If you need more help, let me know, however, trying it by yourself is the way 
> to learn it.
> 
> Is k^2 is too big, well I haven't given it enough thought to know if I can or 
> cannot do it better.
> 
> Regards,
> Carlos Guia
> 
> On Apr 2, 2012 1:28 PM, "vivek dhiman" <[email protected]> wrote:
> + I am only looking at the count..
> 
> for k=1  ans = 1
> k=2 ans = 2
> k=3 ans = 5
> k=4 ans = 14 I guess...
> k = 5 ans =52 I guess
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> Vivek Dhiman
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