Disregard

On 3 Apr 2012, at 04:49, Luke Pebody <[email protected]> wrote:

> http://en.wikipedia.org/wiki/Catalan_number 
> 
> 
> 
> On 3 Apr 2012, at 03:35, vivek dhiman <[email protected]> wrote:
> 
>> Hi..
>> 
>> you are correct ...thanks.. it can be done using DP..
>> and I did it :)
>> On Tue, Apr 3, 2012 at 1:48 AM, Carlos Guia <[email protected]> 
>> wrote:
>> Do you have a constrain on k? It can be done in O(k^2).
>> 
>> Dp(p, k) would be the count the number of arrangements of size k of the 
>> previous number was p. 
>> The transitions aren't hard, there are at most three of them, you should be 
>> able to figure them out.
>> 
>> If you need more help, let me know, however, trying it by yourself is the 
>> way to learn it.
>> 
>> Is k^2 is too big, well I haven't given it enough thought to know if I can 
>> or cannot do it better.
>> 
>> Regards,
>> Carlos Guia
>> 
>> On Apr 2, 2012 1:28 PM, "vivek dhiman" <[email protected]> wrote:
>> + I am only looking at the count..
>> 
>> for k=1  ans = 1
>> k=2 ans = 2
>> k=3 ans = 5
>> k=4 ans = 14 I guess...
>> k = 5 ans =52 I guess
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>> Regards
>> Vivek Dhiman
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