Thank you for your explanations.
i think in your second sentence you mean "...C is next to the back of
B. C and B must therefore be in different lanes..."
So car C oblige car A & B to be in the same lane (and when B overcame
car C, there is car D that cannot permit B to change line)

Now i understand that i cannot say if t is a solution only based by
distance covered by cars


On 30 Apr, 19:49, Luke Pebody <[email protected]> wrote:
> At time t=10.01, the cars are at positions:
> A - [40.04,45.04]
> B - [49.02,54.02]
> C - [45.01,50.01]
> D - [54.01,59.01]
>
> Note that the front of A is next to the back of C. They must be in different 
> lanes, and must stay in those lanes until A fully passed C at time 13.3333.
>
> Note also that the front of C is next to the back of A. C and A must 
> therefore be in different lanes, and so A and B must be in the same lane.
>
> Note also that the front of B is next to the back of D. They must be in 
> different lanes, and must stay in those lanes until B fully passes D at time 
> 20.
>
> So to summarise, from time 10.01 to time 13.333, cars A and B are in the same 
> lane and cannot change lane. Therefore, at time 12 when A reaches B, maximal 
> bang occurs.
>
> On 29 Apr 2012, at 21:16, xenoky <[email protected]> wrote:
>
>
>
>
>
>
>
> > Hi,
>
> > The 4th test case in the Cruise Control problem has the following
> > input:
> > 4
> > L 4 0
> > L 2 29
> > L 1 35
> > L 1 44
>
> > The given solution is:
> > Case #4: 12
>
> > calculating the distance at t=12
>
> > 4*12=48
> > 2*12+29=53
> > 12+35=47
> > 12+44=56
>
> > ordering this distance [47,48,53,56]
>
> > The maximum distance beetween nearest triplet is 6! -> [47,48,53]
>
> > I can put the car this way
>
> > ##### #####
> > #####
>
> > without accident
>
> > Where am i wrong?
>
> > My program answer is 13...
>
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