Yep On 1 May 2012 14:11, "xenoky" <[email protected]> wrote:
> Thank you for your explanations. > i think in your second sentence you mean "...C is next to the back of > B. C and B must therefore be in different lanes..." > So car C oblige car A & B to be in the same lane (and when B overcame > car C, there is car D that cannot permit B to change line) > > Now i understand that i cannot say if t is a solution only based by > distance covered by cars > > > On 30 Apr, 19:49, Luke Pebody <[email protected]> wrote: > > At time t=10.01, the cars are at positions: > > A - [40.04,45.04] > > B - [49.02,54.02] > > C - [45.01,50.01] > > D - [54.01,59.01] > > > > Note that the front of A is next to the back of C. They must be in > different lanes, and must stay in those lanes until A fully passed C at > time 13.3333. > > > > Note also that the front of C is next to the back of A. C and A must > therefore be in different lanes, and so A and B must be in the same lane. > > > > Note also that the front of B is next to the back of D. They must be in > different lanes, and must stay in those lanes until B fully passes D at > time 20. > > > > So to summarise, from time 10.01 to time 13.333, cars A and B are in the > same lane and cannot change lane. Therefore, at time 12 when A reaches B, > maximal bang occurs. > > > > On 29 Apr 2012, at 21:16, xenoky <[email protected]> wrote: > > > > > > > > > > > > > > > > > Hi, > > > > > The 4th test case in the Cruise Control problem has the following > > > input: > > > 4 > > > L 4 0 > > > L 2 29 > > > L 1 35 > > > L 1 44 > > > > > The given solution is: > > > Case #4: 12 > > > > > calculating the distance at t=12 > > > > > 4*12=48 > > > 2*12+29=53 > > > 12+35=47 > > > 12+44=56 > > > > > ordering this distance [47,48,53,56] > > > > > The maximum distance beetween nearest triplet is 6! -> [47,48,53] > > > > > I can put the car this way > > > > > ##### ##### > > > ##### > > > > > without accident > > > > > Where am i wrong? > > > > > My program answer is 13... > > > > > -- > > > You received this message because you are subscribed to the Google > Groups "Google Code Jam" group. > > > To post to this group, send email to [email protected]. > > > To unsubscribe from this group, send email to > [email protected]. > > > For more options, visit this group athttp:// > groups.google.com/group/google-code?hl=en. > > -- > You received this message because you are subscribed to the Google Groups > "Google Code Jam" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]. > For more options, visit this group at > http://groups.google.com/group/google-code?hl=en. > > -- You received this message because you are subscribed to the Google Groups "Google Code Jam" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/google-code?hl=en.
