Hi Igor!
Before I go in and debut your code, will you please explain the logic behind
your solution?
> On Apr 9, 2020, at 11:45 AM, Igor Cha <alenwalke...@gmail.com> wrote:
>
>
> can anyone help out? D:
>
>> On Tuesday, April 7, 2020 at 8:51:58 AM UTC-7, Igor Cha wrote:
>> Hi, I initially approached this using the same way as in the analysis of the
>> problem, but I thought I found a better solution. However, it kept giving me
>> WA and I am trying to figure out why. It passes all the examples
>> successfully as far as I can tell.
>>
>> Could someone please help me out?
>>
>> Thanks. The code is below in java.
>>
>> import java.util.*;
>> import java.io.*;
>> public class Solution {
>> public static void main(String[] args) {
>> Scanner in = new Scanner(new BufferedReader(new
>> InputStreamReader(System.in)));
>> int t = in.nextInt(); // Scanner has functions to read ints, longs,
>> strings, chars, etc.
>> for (int i = 1; i <= t; ++i) {
>> int n = in.nextInt();
>> //schedules for c and j false is free true is busy 0-1440
>> int[] c = new int[1441];
>> int[] j = new int[1441];
>> boolean busyC = false;
>> boolean busyJ = false;
>> boolean impossibleFlag = false;
>> int start = 0;
>> int end = 0;
>> String output = "";
>> //go through n tasks to try and assign
>> for(int x=1; x<=n; x++){
>> start = in.nextInt();
>> end = in.nextInt();
>> if(!impossibleFlag) {
>> for(int k=start; k<end; k++){
>> //check schedule for c and j
>> if(c[k]==1){
>> busyC = true;
>> }
>> if(j[k]==1){
>> busyJ = true;
>> }
>> }
>> if(!busyC){
>> output+="C";
>> //fill C's schedule
>> for(int k=start; k<end; k++){
>> c[k] = 1;
>> }
>> }
>> else if(!busyJ){
>> output+="J";
>> //fill J's schedule
>> for(int k=start; k<end; k++){
>> j[k] = 1;
>> }
>> }
>> else{
>> output="IMPOSSIBLE";
>> impossibleFlag = true;
>> }
>> busyC=false;
>> busyJ=false;
>> }
>> }
>> System.out.println("Case #" + i + ": " + output);
>> }
>> }
>> }
>>
>>
>
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