Since you didn't provide the examples I asked for, I'll do it for you and take a guess about what you mean by friendly URLs. I assume that instead of using URLs like this:
http://www.example.com/index.php?section=one&page=two http://www.example.com/index.php?section=buckle&page=myshoe you want to use URLs like this: http://www.example.com/one/two http://www.example.com/buckle/myshoe Is that correct? So, were you thinking that each of the latter two URLs requires its own Maps API key? They don't. You can simply register one API key for: http://www.example.com/ and use it for *any* page on your site, as long as it's in the same domain. If you want, you can even register a single key for your second level domain: http://example.com/ and use it for any page in any subdomain, such as: http://example.com/ http://example.com/test http://www.example.com/ http://www.example.com/one/two/ http://poohbear.example.com/hovering/over/a/honey/tree Is that what you were worried about? It sounds like you just misunderstood when you need a separate API key and when you don't. -Mike p.s. Don't "demand" answers here. With the exception of Pamela who works for Google, none of us get paid to help you out. We just do it because we're nice people. OK? > From: Frits > > Ok, I'll try again. > > From the beginning. You start of with a key for the use of > the API on your website. This key is limited to a full > HTTP_Referer... Which is ridiculous because if you use the > map on every page of your website together with friendly > URL's you have to get a new key for every page. > A key per domain is a logic solution to the problem. Since > Google so gladly suggest that we all use Friendly URL's. It's > Google who made me use those for getting better ranking > results and now I discover that their own product is in > contradiction with this rule... I really can't understand that. > > So, my question is: What is the solution that my Friendly > URL's work with 1 key? > > And like I already said: "Nasty solutions with questionmarks > in the URL is not a solution." > > I hope you all can help me before I change my mind. Since I > have a deadline for this... > > Thank you. > > Frits > > On Dec 14, 5:05 am, "Michael Geary" <[email protected]> wrote: > > I'm trying to understand what you said, and I can't make > any sense of > > it. I don't think you've asked a question that anyone could answer. > > There are many friendly people in this group who would be happy to > > help you out, but you have to help us help you. :-) > > > > Could you clarify: > > > > * What do you mean by "Friendly URLs"? Specific examples, please? > > > > * How does the Maps API prevent you from using them? > > > > * Can you provide a link to a page where you ran into > whatever problem > > you're referring to? > > > > The Maps API is just a JavaScript API. It really has nothing to do > > with the kind of URL you are using. You do need to get an > API key for > > the domain where you're using the Maps API, but that doesn't affect > > what you put > > *after* the domain name in the URL. > > > > -Mike > > > > > From: Frits > > > > > I'm getting the feeling that Google does not want me to > use the maps > > > API. Because it's not possible together with Friendly > URL's. Though > > > Friendly URL's are damanded for improved Google indexing. > > > Contradiction??? Please explain before I go to MS maps! > > > > > Yes, I know that there are topics about this issue. They > just don't > > > solve the problem. And NO, the questionmark solution is NOT a > > > solution. It's just a nasty way of saying: "Deal with our > > > contradictional rules." > > > > > I'm really curious what the answer is... And if it's > going to send > > > me to MS... > > --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Google Maps API" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/Google-Maps-API?hl=en -~----------~----~----~----~------~----~------~--~---
