> I think that for precise calculation of longitude delta I need
> latitude position  (apart from distance) .
>
> Calculation of latitude delta given in my former post is precise after
> all  (var deltaLat: Number = (distance * 180) / 20000) so don't
> bother.
>

I think I got it:
deltaLongtitude = (distance / (2 * PI * cos(latitude) * radiusEarth))
* 360;

Thanks
Tomek
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