you dont need to target a blank window, since anyway its a new one by default, so just skip the second parameter to $wnd.open() or if you still want to then do like
$wnd.open(url,'_blank'); br, On 22 Jul., 13:30, Paul Grenyer <[email protected]> wrote: > Hi > > On Thu, Jul 22, 2010 at 11:57 AM, cokol <[email protected]> wrote: > > hi, try it as follows: > > > private static native void getURL(String url) > > /*-{ > > $wnd.open('' + url,'target=_blank') > > }-*/; > > Thanks! Unfortunately that didn't work either. Just to see what > happens, I tried: > > private static native void getURL(String url) > /*-{ > $wnd.open('http://www.itv-f1.com/','target=_blank'); > }-*/; > > and I get the same error, which suggests to me maybe it's not the string type. > > -- > Thanks > Paul > > Paul Grenyer > e: [email protected] > b: paulgrenyer.blogspot.com > t: pjgrenyer -- You received this message because you are subscribed to the Google Groups "Google Web Toolkit" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/google-web-toolkit?hl=en.
