What link?

--
David Rutten
Robert McNeel & Associates

On Oct 24, 9:20 pm, K4rl33 <[EMAIL PROTECTED]> wrote:
> First of all, thank you David.
> Substantially, I've solved the problem.
> But now I've still a perplexity: please, look at the algorithm in this
> link: is that the shorter way to obtain the grid that I want?
> Here I've done a cross reference on the F(X) component and then I've
> managed the result with a Z vector to translate the grid of X Y planar
> points and create my grid.
>
> On 24 Ott, 12:29, David Rutten <[EMAIL PROTECTED]> wrote:
>
> > Hi Carlo,
>
> > the Cross reference is supposed to be in the F(x) component.
> > See:http://grasshopper3d.googlegroups.com/web/CrossReferencePointFunction...
>
> > --
> > David Rutten
> > Robert McNeel & Associates
>
> > On Oct 24, 12:47 pm, K4rl33 <[EMAIL PROTECTED]> wrote:
>
> > > Hi guys,
>
> > > I'm playing in grasshopper with the Expressions component.
> > > I have already managed F1(x) functions, and with my alghorithm I can
> > > see the flow of the function in a collection of points that generates
> > > the flow of a curve in a bidimensional space; here there's a diagram
> > > of the logic structure.
>
> > > RANGE------------------------------->  X
> > >                     |                              POINT
> > >                     |---->    F(X)    ---> Y
>
> > > All right at the moment.
>
> > > But now I want to improve from F1(x) functions to F2(x) functions to
> > > study by points the flow in the 3dimensional space.
> > > I take two range components and I join them to the F2(X) component (x
> > > and y with a defined R2 --> R function, for example sin(x+y)), then to
> > > the X and Y of the POINT component, and the F2(X) output to the Z of
> > > the POINT.
> > > What I obtain is not a plane - so a grid - as I want,but a curve
> > > defined by points in the space, on the diagonal of the matrix of
> > > values of the ranges (domains) that I've choosed. If I put "cross
> > > reference" to the POINT component, the diagonal shift to a grid of
> > > points, but in each (X;Y)  value I doesn't have a unique Z = F(X;Y)
> > > result as I want , but multiple results, and it is not good because
> > > the function must associate a unique value to each couple of points.
>
> > > Sorry for my poor english, I hope you guys have understood the problem
> > > and would give me an answer to solve it!
>
> > > K4rl33

Reply via email to