Hi Matt! It works very well!!!! Thank you so much!!!!
On 26 Ott, 05:32, strontium5 <[EMAIL PROTECTED]> wrote: > Hey Carlo, > > try adding 1 to the range that is used and plug that into the U input > of the "surface from grid of points" > > http://grasshopper3d.googlegroups.com/web/SurfaceFromGridOfPoints.jpg... > > -Matt Swarts > Research Scientist, Georgia Tech > > On Oct 25, 9:05 am, K4rl33 <[EMAIL PROTECTED]> wrote: > > > Thank you David, your answer was totally fulfilling. > > I'm sorry if I'm taking advantage from your kindness,but I'd like to > > make you another question. > > Is the grid of point generated from the function able to be used,for > > example to create a surface through, or to populate the cells of the > > grid? > > I've tried with the "surface from points" component, but it doesn't > > work! > > > On 24 Ott, 22:06, David Rutten <[EMAIL PROTECTED]> wrote: > > > > Hi Carlo, > > > > there are 2 fairly simple ways in which you can do this: > > > > 1) Create the point grid directly in the > > > expression:http://grasshopper3d.googlegroups.com/web/CreatePointsInExpression.jp... > > > > 2) Create the point grid using a Point(xyz) component (Cross Reference > > > mode) and then adjust them using an > > > expression:http://grasshopper3d.googlegroups.com/web/AdjustPointsInExpression.jp... > > > > Both these methods involve making point objects *inside* the > > > expression. > > > > You could also choose to make an offset expression. One input > > > parameter (point): > > > > p + {Sin(p.y),Cos(p.x),Sin(p.x)} > > > > which creates a new vector (inside the curly brackets) and adds that > > > vector to the point coordinates. This effectively distorts the point > > > grid in all 3 dimensions. > > > > -- > > > David Rutten > > > Robert McNeel & Associates > > > > On Oct 24, 10:09 pm, K4rl33 <[EMAIL PROTECTED]> wrote: > > > > >http://groups.google.com/group/grasshopper3d/web/Grid.jpg > > > > > Here's the link. Sorry for the confusion :( > > > > > On 24 Ott, 20:33, David Rutten <[EMAIL PROTECTED]> wrote: > > > > > > What link? > > > > > > -- > > > > > David Rutten > > > > > Robert McNeel & Associates > > > > > > On Oct 24, 9:20 pm, K4rl33 <[EMAIL PROTECTED]> wrote: > > > > > > > First of all, thank you David. > > > > > > Substantially, I've solved the problem. > > > > > > But now I've still a perplexity: please, look at the algorithm in > > > > > > this > > > > > > link: is that the shorter way to obtain the grid that I want? > > > > > > Here I've done a cross reference on the F(X) component and then I've > > > > > > managed the result with a Z vector to translate the grid of X Y > > > > > > planar > > > > > > points and create my grid. > > > > > > > On 24 Ott, 12:29, David Rutten <[EMAIL PROTECTED]> wrote: > > > > > > > > Hi Carlo, > > > > > > > > the Cross reference is supposed to be in the F(x) component. > > > > > > > See:http://grasshopper3d.googlegroups.com/web/CrossReferencePointFunction... > > > > > > > > -- > > > > > > > David Rutten > > > > > > > Robert McNeel & Associates > > > > > > > > On Oct 24, 12:47 pm, K4rl33 <[EMAIL PROTECTED]> wrote: > > > > > > > > > Hi guys, > > > > > > > > > I'm playing in grasshopper with the Expressions component. > > > > > > > > I have already managed F1(x) functions, and with my alghorithm > > > > > > > > I can > > > > > > > > see the flow of the function in a collection of points that > > > > > > > > generates > > > > > > > > the flow of a curve in a bidimensional space; here there's a > > > > > > > > diagram > > > > > > > > of the logic structure. > > > > > > > > > RANGE-------------------------------> X > > > > > > > > | POINT > > > > > > > > |----> F(X) ---> Y > > > > > > > > > All right at the moment. > > > > > > > > > But now I want to improve from F1(x) functions to F2(x) > > > > > > > > functions to > > > > > > > > study by points the flow in the 3dimensional space. > > > > > > > > I take two range components and I join them to the F2(X) > > > > > > > > component (x > > > > > > > > and y with a defined R2 --> R function, for example sin(x+y)), > > > > > > > > then to > > > > > > > > the X and Y of the POINT component, and the F2(X) output to the > > > > > > > > Z of > > > > > > > > the POINT. > > > > > > > > What I obtain is not a plane - so a grid - as I want,but a curve > > > > > > > > defined by points in the space, on the diagonal of the matrix of > > > > > > > > values of the ranges (domains) that I've choosed. If I put > > > > > > > > "cross > > > > > > > > reference" to the POINT component, the diagonal shift to a grid > > > > > > > > of > > > > > > > > points, but in each (X;Y) value I doesn't have a unique Z = > > > > > > > > F(X;Y) > > > > > > > > result as I want , but multiple results, and it is not good > > > > > > > > because > > > > > > > > the function must associate a unique value to each couple of > > > > > > > > points. > > > > > > > > > Sorry for my poor english, I hope you guys have understood the > > > > > > > > problem > > > > > > > > and would give me an answer to solve it! > > > > > > > > > K4rl33- Hide quoted text - > > > - Show quoted text -
