On 23 February 2018 at 14:55, Pavlo Solntsev wrote: > Daniel, > > now it is clear. I didn't and still don't understand exactly how internal > data members are represented in the generated class (I have no access to my > code now) but the situation I have by returning a reference is clear. BTW > does it make sense to think about shared_ptr as returned value for getter? >
No, because unless you keep a copy of the shared_ptr as a member, you will get a new shared_ptr each time you call it, which doesn't share ownership with the previous ones. So now you have the shared_ptr overhead (reference counting) and inconvenience (needing to use operator* to access the value), without any sharing. You might as well just return by value, or have a Glib::ustring member.
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