On 4/3/14 03:52, Behdad Esfahbod wrote:
On 14-03-01 08:38 AM, Werner LEMBERG wrote:
Compiling with -ansi using
i686-apple-darwin11-llvm-gcc-4.2 (GCC) 4.2.1
(Based on Apple Inc. build 5658) (LLVM build 2336.11.00)
I get the following warning:
hb-common.h:280: warning:
ISO C restricts enumerator values to range of 'int'
Nothing really serious, but probably worthwhile to mention...
Humm. I was under the impression that the compiler chooses unsigned int if
necessary. Don't know. We definitely want hb_tag_t to be equivalent to
unsigned. Jonathan, WDYT?
This isn't a problem in C++, AIUI, but only for C clients that include
the header. ISO C says:
Each enumerated type shall be compatible with char, a signed
integer type, or an unsigned integer type. The choice of type is
implementation-defined, but shall be capable of representing the
values of all the members of the enumeration.
which is fine, but it also says:
The expression that defines the value of an enumeration constant
shall be an integer constant expression that has a value
representable as an int.
That's what leads to the pedantic warning: we have HB_TAG_MAX defined as
the hb_tag_t value of 0xffffffff, and hb_tag_t is uint32_t, so this is
the integer 4294967295, which is not representable as an int.
If we change the last value in the hb_script_t enumeration to
/*---*/ _HB_SCRIPT_MAX_VALUE = (int) HB_TAG_MAX
i.e. add an explicit cast, then I believe we shouldn't get a warning.
However, this might mean the compiler will choose to represent the
hb_script_t enumeration as int instead of unsigned int (because one of
its values will be negative). But AFAICT this should be harmless.
Werner, could you confirm that adding the (int) cast there fixes the
warning in your build? Thanks.
JK
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