(opss just noticed I did a reply-to) > > The following is closer to the original, but doesn't work when the whole > > list is folded (i.e., p always satisfied): > > foldlWhile f p a = head . dropWhile p . scanl f a > > Serge's version returns the last 'a' that satisfies 'p', while yours Not really.
> returns the first 'a' that does not satisfy 'p'. This should be an > equivalent version: Yeap, just like his, foldlWhile :: (a -> b -> a) -> (a -> Bool) -> a -> [b] -> a foldlWhile f p a bs = <snip> (_, False) -> a <snip> It tests the accumulator with p, and returns it on "false". J.A. _______________________________________________ Haskell-Cafe mailing list [EMAIL PROTECTED] http://www.haskell.org/mailman/listinfo/haskell-cafe
