To my question of >> foldlWhile :: (a -> b -> a) -> (a -> Bool) -> a -> [b] -> a >> foldlWhile f p a bs = >> case >> (bs, p a) >> of >> ([], _ ) -> a >> (_, False) -> a >> (b:bs', _ ) -> foldlWhile f p (f a b) bs' >> >> foldl does not seem to cover this.
Dylan Thurston wrote: On Nov 20, 2004 > An alternative is > > foldlWhile f p a bs = last $ takeWhile p $ scanl f a bs > Yes. Thank you. Inspecting Prelude, we find out that scanl expresses, mainly, the thing. ----------------- Serge Mechveliani [EMAIL PROTECTED] _______________________________________________ Haskell-Cafe mailing list [EMAIL PROTECTED] http://www.haskell.org/mailman/listinfo/haskell-cafe
