Can a kind soul please enlighten me on why f bit0 and f bit1 both return 0?
> bit0 = False > bit1 = True > f x = case x of > bit0 -> 0 > bit1 -> 1 _______________________________________________ Haskell-Cafe mailing list [email protected] http://www.haskell.org/mailman/listinfo/haskell-cafe
