Imagine if bar was a toplevel function bar = case foo of True -> " Foo"; False -> "Bar";
Keep in mind that indentation level starts at the function name, not at the let keyword. On Thu, Oct 3, 2013 at 2:31 PM, Corentin Dupont <corentin.dup...@gmail.com>wrote: > Hi the list, > why do this function doesn't compile (parse error): > > test :: Bool -> IO () > test foo = do > let bar = case foo of > True -> "Foo"; > False -> "Bar" > return () > > while this one does (just adding one space in front of True and False): > > test :: Bool -> IO () > test foo = do > let bar = case foo of > True -> "Foo"; > False -> "Bar" > return () > > > Thanks!! > Corentin > > _______________________________________________ > Haskell-Cafe mailing list > Haskell-Cafe@haskell.org > http://www.haskell.org/mailman/listinfo/haskell-cafe > >
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